For the coagulation of 200 mL of As 2 S 3 solution, 10 mL o…

Chemistry Surface Chemistry General Numeric Response

Published on: August 13, 2026

For the coagulation of 200 mL of As 2 S 3 solution, 10 mL of 1 M NaCl is required. What is the coagulating value of NaCl.

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The correct answer is:

Sol. 10 ml of 1 M NaCl contains NaCl = 10 × 1 = 10 milli mole

200 ml of As 2 S 3 required NaCl for the coagulation = 10 milli mole

∴ 1000 ml of As 2 S 3 required NaCl for the coagulation = 10 × 1000/ 200 = 50 milli mole

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